First slide

Simple harmonic motion

Question

Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing S.H.M. is

Easy

A

– a
B

+ a
C

$\pm a$
D

$\pm \frac{a}{4}$

Solution

Maximum potential energy position is $y = \pm a$
and maximum kinetic energy position is $y =0$

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