First slide

Instantaneous velocity

Question

The displacement of a body along X-axis depends on time as $\sqrt{x} = t + 1$ . Then, the velocity of body

Moderate

A

increases with time
B

decreases with time
C

independent of time
D

None of these

Solution

Given, $\sqrt{x} = t + 1$
Squaring both sides, we get
$x = (t + 1)^{2} = t^{2} + 2 t + 1$
Differentiating it w.r.t. timet, we get
$\frac{d x}{d t} = 2 t + 2$
Velocity, $v = \frac{d x}{d t} = 2 t + 2$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App