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Questions  

The displacement equation of a particle is x=3sin2t+4cos2t.  The amplitude and maximum velocity will be respectively

a
5, 10
b
3, 2
c
4, 2
d
3, 4

detailed solution

Correct option is A

x=3sin2t+4cos2t. From given equation a1=3, a2=4, and φ=π2∴a=a12+a22 =32+42=5  ⇒vmax=aω=5×2=10

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