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Q.

The displacement equation of a particle is x=3sin2t+4cos2t.  The amplitude and maximum velocity will be respectively

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a

5, 10

b

3, 2

c

4, 2

d

3, 4

answer is A.

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Detailed Solution

x=3sin2t+4cos2t. From given equation a1=3, a2=4, and φ=π2∴a=a12+a22 =32+42=5  ⇒vmax=aω=5×2=10
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