Download the app

Questions  

The displacement equation of a particle is is x=(3sin2t+4cos2t)cm. Then magnitude of maximum acceleration of the particle is 

a
60 cms2
b
10 cms2
c
20 cms2
d
40 cms2

detailed solution

Correct option is C

x=3sin2t+4cos2t=32+42sin(2t+tan-14/3)∴A=Amplitude=5cmω=2rad/sec∴ Maximum acceleration =ω2A=(2)2×5cm/s2=20cm/s2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

One end of an ideal spring is connected with a smooth block with the other end with rear wall of driving cabin of a truck as shown in figure. Initially, the system is at rest. If truck starts to accelerate with a constant acceleration ‘a’ , then the block (relative to truck ):


phone icon
whats app icon