Displacement of a particle executing SHM can be expressed as $\mathrm{x}=\mathrm{a} \sin \left(\mathrm{\omega t}+\mathrm{\delta }\right)$At t = 0, it is observed that the particle is at $\mathrm{x}=\frac{\mathrm{a}}{2}$ and, moving along positive r-direction. Then $\mathrm{\delta }$ could be:

• A

  $\frac{\mathrm{\pi }}{3}$

• B

  $\frac{\mathrm{\pi }}{6}$

• C

  $\frac{5\mathrm{\pi }}{6}$

• D

  $\frac{\mathrm{\pi }}{4}$