Questions
The displacement of a particle executing simple harmonic motion is given by . Then the amplitude of its oscillation is given by
detailed solution
Correct option is C
y = A0+(A sin ωt + B cos ωt) = A0+Asin ωt+B sin(ωt+π2)Hence 2 SHMs are superimposed with phase difference of π2Amplitude a = A2+B2+2ABcos∆∅As, ∆∅ = π2 Hence a = A2+B2y = A0+A2+B2 sin(ωt6ϕ)A0 is mean position, and A2+B2 is amplitudeTalk to our academic expert!
Similar Questions
A charged particle is deflected by two mutually perpendicular oscillating electric fields such that the displacement of the particle due to each one of them is given by respectively. The trajectory followed by the charged particle is
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