Download the app

Questions  

The displacement of a particle executing simple harmonic motion is given by 
x = a sin ωt + a cos ω
The total energy of the particle is

a
12 ma2ω2
b
m a2ω2
c
14 ma2ω2
d
2ma2ω2

detailed solution

Correct option is B

Given x = a sin ωt + a cos ωt                …….. (1)The displacement equation of a simple harmonic motion is x = A sin (ωt + ϕ)where A = amplitude and ϕ = phase constant. x = A sin ωt cosϕ + A cos ωt sin ϕ         …….. (2)Comparing (1) with (2) we get A cos ϕ = a    (3)and A sin ϕ = a    (4)Squaring and adding Eqs. (3) and (4) we get A2 = a2 + a2  ⇒   A2 = 2a2∴ Energy =   12 m   ω2 A2 = m   ω2 a2So the correct choice is (b).

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A charged particle is deflected by two mutually perpendicular oscillating electric fields such that the displacement of the particle due to each one of them is given by x = A sin (ωt) and y = A sin (ωt+π6) respectively. The trajectory followed by the charged particle is


phone icon
whats app icon