The displacement of a particle as a function of time is shown in the figure. The figure shows that

Easy

A

The particle starts with certain velocity but the motion is retarded and finally the particle stops
B

The velocity of the particle is constant throughout
C

The acceleration of the particle is constant throughout
D

The particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity.

Solution

After a long time the displacement becomes constant i.e. The particle stops, since v = dx/dt, it is evident from the graph of x vs t, that dx/dt is non-zero at t = 0 and dx/dt i.e. v decreases with the increase in time, Therefore moiton of the particle is retarded motion.

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