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The displacement of a particle of mass 3g executing simple harmonic motion is given by x=3sin(0.2t) in SI units. The kinetic energy of
the particle at a point which is at a displacement equal to 1/3 of its amplitude from its mean position is

a
12×10-3 J
b
25×10-3 J
c
0.48×10-3 J
d
0.24×10-3 J

detailed solution

Correct option is C

K.E. =12mω2A2-x2

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