The displacement of a particle of mass 3g executing simple harmonic motion is given by x=3sin(0.2t) in SI units. The kinetic energy ofthe particle at a point which is at a displacement equal to 1/3 of its amplitude from its mean position is

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12×10-3 J

25×10-3 J

0.48×10-3 J

0.24×10-3 J

answer is C.

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Detailed Solution

K.E. =12mω2A2-x2

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