Download the app

Questions  

The displacement of a particle moving in a straight line is described by the relation S=6+12t-2t2. Here s in meter and t is in sec. The distance covered by the particle in first 5s is

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
20m
b
24m
c
16m
d
26m

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is D

s=6+12t−2t2differentiating with respect to tv=12−4tdirection is reversed , v=0at time, t = 3sAt t=0,The displacement is 6 metersdisplacement in 3 secs is 6+12(3)−2(3)2=24 displacement in 5 secs is 6+12(5)−2(5)2=16 Distance travelled in forward direction in 3 sec is 24-6=18 mDistance travelled in reverse direction in next 2 sec is 24-16=8 mThus total distance travelled in 5 sec= 18+8=26 m

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?

ctaimg

Create Your Own Test
Your Topic, Your Difficulty, Your Pace


Similar Questions

A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms-1. Assuming constant acceleration, the approximate time that it spends in the barrel after the gun is fired is


phone icon
whats app icon