The displacement of a particle is represented by the equation y=5 cos3π2−2π t where y is displacement ω is angular frequency in metre and t is given in instant of time in h the motion of the particle is
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a
simple harmonic with period of 1-hour
b
simple harmonic with a time period of 2πωs
c
periodic but not simple harmonic
d
simple harmonic with time period of 2πωs
answer is A.
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Detailed Solution
The equation y=5 cos3π2−2π t represents simple harmonic motion which takes the form y=5 sin2π t+π2 The equation y=5 cos3π2−2π t can be Written asy=5cos2πt−3π2(∵cos(−θ)=cosθ)⇒y=5cosπ2+2πt−2π∵3π2=2π−π2⇒y=5cosπ2+2πt(∵cos(2π−θ)=cosθ)y=−5sin2πt∵cosπ2+θ=−sinθHence time period is 1 hour