The displacement of a particle is represented by the equation y=5 cos3π2−2π t where y is displacement ω is angular frequency in metre and t is given in instant of time in sec the motion of the particle is
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a
simple harmonic with period of 1sec
b
simple harmonic with a time period of 2πω hour
c
periodic but not simple harmonic
d
simple harmonic with time period of 2ωs
answer is A.
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Detailed Solution
The equation y=5 cos3π2−2π t represents simple harmonic motion which takes the form y=5 sin2π t+π2 The equation y=5 cos3π2−2π t represents simple harmonic motion The equation y=5 cos3π2−2π t can be Written asy=5 cos2π t−3π2 ∵cos(−θ)=cosθ ⇒y=5 cosπ2+2π t−2π ∵3π2=2π−π2⇒y=5 cosπ2+2π t ∵ cos2π−θ=cosθ y=−5 sin2π t ∵ cosπ2+θ=−sinθ compare with y=Asinωt we get ω=2π we know, ω=2πT ⇒2πT=2π ⇒T=1 sec time period