The displacement of particle starting from rest is given by S=3t2 - t3 , where t is in sec.The particle will come to rest again at time of
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a
t=2sec
b
t=3sec
c
t=4sec
d
t=5sec
answer is A.
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Detailed Solution
displacement=S=3t2−t3to find velocity, differentiate above equation with respect to time Velocity V=dsdt⇒V=ddt3t2−t3V=6t−3t2 If V=00=6t−3t2⇒6t=3t2⇒t=63⇒t=2sec