Download the app

Questions  

The displacement of a particle varies with time as x = 12 sin ωt - 16 sin3 ωt (in cm). If its motion is S.H.M., then its maximum acceleration is

a
12ω2
b
36ω2
c
133ω2
d
192 ω2

detailed solution

Correct option is B

x = 12 sin ωt - 16 sin3 ωt = 4[3 sin ωt - 4 sin3 ωt]= 4[sin 3 ωt](By using sin 3θ = 3 sin θ -4 sin3θ)∴  maximum acceleration Amax = (3ω)2×4 = 36ω2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A charged particle is deflected by two mutually perpendicular oscillating electric fields such that the displacement of the particle due to each one of them is given by x = A sin (ωt) and y = A sin (ωt+π6) respectively. The trajectory followed by the charged particle is


phone icon
whats app icon