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The displacement of a particle varies with time as $x = 12 sinωt - 16 \sin^{3} ωt$ (in cm). If its motion is S.H.M., then its maximum acceleration is

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detailed solution

Correct option is B

x=12sinω t−16 sin3ω t=4[3sinω t−4sin3ω t] =4[sin3ω t] (By using sin3θ=3sinθ−4sin3θ)∴ maximum acceleration Amax=(3ω)2×4=36ω2

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The displacement of a particle varies with time as x=12sinωt−16sin3ωt (in cm). If its motion is S.H.M., then its maximum acceleration is

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Ready to Test Your Skills?

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The displacement of a particle varies with time as $x = 12 sinωt - 16 \sin^{3} ωt$ (in cm). If its motion is S.H.M., then its maximum acceleration is