Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The displacement of particle varies with time as x=at2−bt3. Then find the displacement  of the particle when  its acceleration is zero

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

2a327b2

b

27b22a3

c

27a32b2

d

2a39b2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

x=at2−bt3  at t=0⇒x=0to find velocity, differentiate x with respect to time Velocity =V=dxdt=2at−3bt2to find acceleration, differentiate again x with respect to time Acceleration= a=dvdt=2a−6bt If a=0 2a−6bt=0⇒t=a3b=time The position at, time t=a3bx=at2−bt3⇒x=aa3b2−ba3b3⇒x=a39b2−a327b2=2a327b2 Displacement S=2a327b2−0⇒S=2a327b2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring