The displacement of particle varies with time as x=at2−bt3. Then find the displacement of the particle when its acceleration is zero
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a
2a327b2
b
27b22a3
c
27a32b2
d
2a39b2
answer is A.
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Detailed Solution
x=at2−bt3 at t=0⇒x=0to find velocity, differentiate x with respect to time Velocity =V=dxdt=2at−3bt2to find acceleration, differentiate again x with respect to time Acceleration= a=dvdt=2a−6bt If a=0 2a−6bt=0⇒t=a3b=time The position at, time t=a3bx=at2−bt3⇒x=aa3b2−ba3b3⇒x=a39b2−a327b2=2a327b2 Displacement S=2a327b2−0⇒S=2a327b2