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Questions  

The displacement time graph of a particle executing S.H.M. is given in figure: (sketch is schematic and not to scale)

Which of the following statements is/are true for this motion?

(A) The force is zero at  t=3T4
(B) The acceleration is maximum at t = T
(C) The speed is maximum at  t=T4
(D) The P.E. is equal to K.E. of the oscillation at  t=T2

a
(B), (C) and (D)
b
(A), (B) and (C)
c
(A), (B) and (D)
d
(A) and (D)

detailed solution

Correct option is B

In SHM  a=−ω2xSo when x is max  ⇒ acceleration is maximumWhen x is zero ⇒  acceleration is zero ⇒  Force is zero & velocity is max.PE & KE are equal when  x=±A2

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Similar Questions

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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