Q.

The displacement time graph of a particle executing S.H.M. is given in figure: (sketch is schematic and not to scale)Which of the following statements is/are true for this motion?(A) The force is zero at  t=3T4(B) The acceleration is maximum at t = T(C) The speed is maximum at  t=T4(D) The P.E. is equal to K.E. of the oscillation at  t=T2

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a

(B), (C) and (D)

b

(A), (B) and (C)

c

(A), (B) and (D)

d

(A) and (D)

answer is B.

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Detailed Solution

In SHM  a=−ω2xSo when x is max  ⇒ acceleration is maximumWhen x is zero ⇒  acceleration is zero ⇒  Force is zero & velocity is max.PE & KE are equal when  x=±A2
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