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The displacement of two identical particles executing S.H.M are represented by equation $x_{1} = 4 \sin (10 t + π / 6) a n d x_{2} = 5 \cos (w t)$ . For what value of 'w' energy of both the particles is same.

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detailed solution

Correct option is A

total energy of simple harmonic oscillator E=12mA2ω2 m is mass; A is amplitude; ω is angular velocity given E1=E2 12mA1 2ω12=12mA2 2ω22 ⇒A1ω1=A2ω2 ; by question A1=4; w1=10; A2=5 ; substitute them ⇒ 4x10=5 ω22 ⇒ω2=8 units.

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The displacement of two identical particles executing S.H.M are represented by equation x1=4sin(10t+π/6) and x2=5cos(wt). For what value of 'w' energy of both the particles is same.

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The displacement of two identical particles executing S.H.M are represented by equation $x_{1} = 4 \sin (10 t + π / 6) a n d x_{2} = 5 \cos (w t)$ . For what value of 'w' energy of both the particles is same.