The displacement x in meter of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in second by the equation x = (t - 3)2. The work done by the force (in joules) in first six seconds is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

18 m

Zero

9 m/2

36 m

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Here x=(t−3)2=t2−6t+9 v=dxdt=2t−6At t=0,v=2×0−6=−6At t=6s,v=2×6−6=+6Initial and final KE are same, hence no work is done

Watch 3-min video & get full concept clarity