The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force is related to time ‘t’ (in s ) by t = x+3. The displacement of the particle when its velocity is zero will be

We are given t = x+3⇒ x = t-3    ⇒x = (t-3)2  ----(i)Differentiating equation (i) we get velocityv = dxdt= 2(t-3)    -----(ii)For the velocity of the particle will be zero.v = dxdt = 0  ⇒t = 3 sThe displacement of the particle when its velocity is zero x = (3-3)2    ⇒ x = 0