The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = x+3, where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is
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a
9 J
b
6 J
c
0 J
d
3 J
answer is C.
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Detailed Solution
x = (t-3)2 ⇒ v = dxdt = 2(t-3)at t = 0; v1 = -6 m/s and at t = 6 sec, v2 = 6 m/sso, change in kinetic energy = W = 12mv22- 12mv12 = 0
The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = x+3, where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is