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Q.

The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t=x+3, where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is

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a

9 J

b

6 J

c

0 J

d

3 J

answer is C.

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Detailed Solution

x=(t−3)2⇒v=dxdt=2(t−3) at t=0;v1=−6m/s and at t=6sec,v2=6m/sso, change in kinetic energy =W=12mv22−12mv12=0

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