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Q.

The displacement x of a particle moving in a straight line varies with time t as x2=a+bt2 where a and b are constants. The acceleration of the particle at time t is given by

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a

ax−bt2x3

b

ax−btx2

c

bx−b2t2x3

d

ax−atx2

answer is C.

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Detailed Solution

x2=a+bt2.Differentiating w.r.t time t,2xdxdt=2bt ⇒ dxdt=btx ⇒ v=btxAcceleration =dvdt =ddtbtx =bx−btx2dxdt =bx−btx2btx =bx1−bt2x2
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