The displacement x of a particle at time t moving along a straight line path is given by x2=at2+2bt+c Where a, b and c are constants the acceleration of the particle varies as
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a
x-1
b
x-2
c
x-3
d
x-4
answer is C.
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Detailed Solution
x2=at2+2bt+cDiff wrt ‘t’ we get xv = at + bAgain diff wrt ‘t’ we get xdvdt=a-v2Acceleration =a-v2xA=a-at+bx2xSolving A α x-3