Displacement-time equation of a particle executing SHM is x=10sinπ3t+π6cm. The  distance covered by particle in first 3 seconds is

given displacement equation =x=10sin(π3t+π6) cm compare with standard displacement equation→x=Asin(ωt+∅) we get, amplitude A=10cm;angular velocity=ω=π3 ω=2πT=π3 ⇒T=6sec distance covered in one time period=4×amplitude distance covered in one time period i.e. in 6 sec=40cm distance covered in 3 sec=20cm