The distance between the plates of a parallel plate condenser is 8 mm and P.D. 120 volts. If a 6 mm thick slab of dielectric constant 6 is introduced between its plates, then
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a
The charge on the condenser will be doubled
b
The charge on the condenser will be reduced to half
c
The P.D. across the condenser will be 320 volts
d
The P.D. across the condenser will be 45 volts
answer is D.
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Detailed Solution
If nothing is said, it is considered that battery is disconnected. Hence charge remain the sameAlso Vair =σε0×d and Vmedium =σε0d−t+tk⇒VmVa=d−t+tkd⇒Vm120=8−6+668⇒Vm=45V