Questions
The distance between the plates of a parallel plate Condenser is 4mm and potential difference is 60olts. If the distance between the plates is increased to12mm, then
detailed solution
Correct option is A
For an isolated capacitor charge and hence electric field remains unchanged on changing the separation so E=V/d= Constant. Or V1V2=d1d2⇒ V2=V1×d2d1=60×124=180 VTalk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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