The distance between the plates of a parallel plate Condenser is 4mm and potential difference is 60olts. If the distance between the plates is increased to12mm, then
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a
The potential difference of the condenser will become 180 volts
b
The PD. will become 200 volts
c
The PD. will remain unchanged
d
The charge on condenser will reduce to one third
answer is A.
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Detailed Solution
For an isolated capacitor charge and hence electric field remains unchanged on changing the separation so E=V/d= Constant. Or V1V2=d1d2⇒ V2=V1×d2d1=60×124=180 V