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Distance between two places is 200 km. $α$ of steel $12 \times 10^{- 6} /^{o} C$ . Total space that must be left between steel rails to allow for a change of temperature from $90 ° C$ to is $100 ° C$

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1.08 km

0.024 km

10.8 km

0.048 km

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detailed solution

Correct option is B

l2=l1αΔt=200×12×10−6×10=24×10−3=0.024km

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Distance between two places is 200 km. α of steel 12×10−6/oC . Total space that must be left between steel rails to allow for a change of temperature from 90°C to is 100°C

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Distance between two places is 200 km. $α$ of steel $12 \times 10^{- 6} /^{o} C$ . Total space that must be left between steel rails to allow for a change of temperature from $90 ° C$ to is $100 ° C$