First slide

Magnetic field due to a straight current carrying wire

Question

At a distance of 10 cm from a long straight wire carrying current, the magnetic field is 0.04 T. At the distance of 40 cm, the magnetic field will be

Easy

A

0.01 T
B

0.02 T
C

0.08 T
D

0.16 T

Solution

$B \propto \frac{I}{r} \Rightarrow \frac{B_{1}}{B_{2}} = \frac{r_{2}}{r_{1}} \Rightarrow \frac{0 .04}{B_{2}} = \frac{40}{10} \Rightarrow B_{2} = 0 .01 T$

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