The distance ratio of distance travelled in 1S, 2S, 3S,.......ns is

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1:4:9:.....n2

1:2:3:......n

1:12:13:.......1n

1:1:1:....

answer is A.

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Detailed Solution

In 1st sec the distance traveled is S1=12gt2=g2 In 2nd sec the distance traveled is S2=12gt2=4g2 In 3rd sec the distance traveled is S3=12gt2=9g2S1:S2:S3:.......=g2:4g2:9g2:.......... 1:4:9:........n2

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