First slide

Rectilinear Motion

Question

The distance travelled by a particle starting from rest and moving with a uniform acceleration of $\frac{4}{3} m / s^{2}$ in the 3^rd sec is…m

Moderate

Solution

Given that $u = 0 n = 3 a = \frac{4}{3} m / s^{2}$
From equation $s_{n} = u + a (n - \frac{1}{2})$
$\begin{array}{l} = 0 + \frac{4}{3} (3 - \frac{1}{2}) \\ = \frac{4}{3} (\frac{5}{2}) \\ = \frac{10}{3} \\ = 3.33 m \end{array}$

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