Questions
At distances of 5 cm and 10 cm from the surface of a sphere, the potentials are 600 V and 420 V. Find the potential at its surface
a
650 V
b
850 V
c
1050 V
d
1250 V
detailed solution
Correct option is C
potential at distance 5cm from the surface kqr+0.05=600 V ---1 potential at a distance 10 cm from the surface kqr+0.1= 420 V ----2 dividing we get r= 0.2/3 potential at the surface kqr=v ----3 dividing 1 by 3 we get v=1050 VTalk to our academic expert!
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