Questions
Diwali rocket is ejecting 50 g of gases/s at a velocity of 400 ms-1. The accelerating force on the rocket
will be [RPMT 2011]
a
22 dyne
b
20 N
c
20 dyne
d
100 N
detailed solution
Correct option is B
The accelerating force on the rocket = upward thrust=ΔmΔt·vGiven, ΔmΔt=50×10-3kgs-1and v=400 ms-1So, accelerating force =50×10-3×400=20 NTalk to our academic expert!
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In the figure given the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 s is :
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