First slide

The lens

Question

A double convex lens $(R_{1} = R_{2} = 10 cm) (μ = 1 .5)$ having focal length equal to the focal length of a concave mirror. The radius of curvature of the concave mirror is

Moderate

A

10 cm
B

20 cm
C

40 cm
D

15 cm

Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) = (1 .5 - 1) (\frac{1}{10} + \frac{1}{10}) = \frac{1}{10} \Rightarrow f = 10 cm ∴ Radius of curvature of concave mirror = 2 f = 20 cm .$

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