A double convex thin lens made of glass (refractive index μ = 1.5) has both radii of curvature of magnitude 20 cm. Incident light rays parallel to the axis of the lens will converge at a distance L such that

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L = 20 cm

L = 10 cm

L = 40 cm

L = 203cm

answer is A.

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Detailed Solution

1f=(μ−1)1R1−1R2 Given R1=+20cm,R2=−20cm,μ=1.5 ⇒f=20cm. Parallel rays converge at focus. So L=f.

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