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In a double slit arrangement fringes are produced using light of wavelength 4800Å. One slit is covered by a thin plate of glass of refractive index 1.4 and the other with another glass plate of same thickness but of refractive index 1.7. By doing so the central bright shifts to original fifth bright fringe from centre. Thickness of glass plate is

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Detailed Solution

Shift Δx=βλ(μ−1)tShift due to one plate Δx1=βλμ1−1Shift due to another path Δx2=βλμ2−1tNet shift Δx=Δx2−Δx1=βλμ2−μ1t …(i)Also it is given that x=5β …(ii)Hence 5β=βλμ1−μ2t⇒t=5λμ1−μ2=5×4800×10−10(1.7−1.4)=8×10−6m=8μm

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