First slide

Young's double slit Experiment

Question

A double slit experiment is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and screen 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is $6300 Å.$ Then the fringe width is

Moderate

A

$6.3 \times 10^{- 4} m$
B

$8.3 \times 10^{- 4} m$
C

$6.3 \times 10^{- 2} m$
D

$6.3 \times 10^{- 5} m$

Solution

The experimental setup is in a liquid, therefore the wavelength of light will change.
$λ_{liquid} = \frac{λ_{air}}{μ} = \frac{6300}{1.33}$
$= \frac{6300 \times 10^{- 10}}{1.33} m$
Fringe width
$β = \frac{λ_{liquid} D}{d} = \frac{λ_{air} D}{μd} = \frac{6300 \times 10^{- 10}}{1 .33} \times \frac{1 .33}{10^{- 3}}$
$= 6.32 \times 10^{- 4} m$

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