A double slit experiment is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and screen 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. Then the fringe width is
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a
6.3×10−4m
b
8.3×10−4m
c
6.3×10−2m
d
6.3×10−5m
answer is A.
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Detailed Solution
The experimental setup is in a liquid, therefore the wavelength of light will change.λliquid =λair μ=63001.33=6300×10−101.33mFringe widthβ=λliquid Dd=λair Dμd=6300×10−101.33×1.3310−3=6.32×10−4m