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Q.

A double slit experiment is immersed in a liquid of refractive index 1.33. It has slit separation of 1mm and distance between the plane of slits and screen 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300A0 .Find fringe width

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a

6.3×10−4m

b

8.3×10−4m

c

6.3×10−2m

d

6.3×10−5m

answer is A.

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Detailed Solution

The experimental setup is in a liquid, therefore the wavelength of light will change.λliquid=λairμ=63001.33=6300×10−161.33mFringe width β=λliquidDd=λairDμd=6300×10−101.33×1.3310−3=6.3×10−4m

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