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Q.

In double slit experiment, a light of wavelength λ=600  nm is used. When a film of material 3.6×10−3 cm  thick was placed over one of the slits, the fringe patternwas displaced by a distance equal to 30  times that between two adjacent fringes. What is the refractive index of the martial?

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a

1.5

b

7.2

c

8.1

d

5.5

answer is A.

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Detailed Solution

Wavelength λ=600 nm=600×10−9 m Thickness t=3.6×10−3 cm Number of fringes n=30 Refractive index μ=nλt+1     ( ∵  n=(μ−1)tλ )                                 =30×6×10−73.6×10−5+1                              =0.5+1                      ∴  μ=1.5
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