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Q.

A double slit experiment is performed with light of wavelength 500 nm. A thin film of thickness 2 μm  and refractive index 1.5 is introduced in the path of the upper beam. The location of the central maximum will

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a

remain unsuited

b

shift downward by nearly two fringes

c

shift upward by nearly two fringes

d

shift downward by 10 fringes

answer is C.

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Detailed Solution

The given values are λ=500 nm=500×10−9m t=2μm=2×10−6m μ=1.5 Number of fringes shifted n=(μ−1)tλ n=(1.5−1)2×10−6500×10−9 n=0.5×2×10−65×10−7 ∴n=2 Shift upwards nearly two fringe.
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