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Q.

A double slit experiment is performed with light of wavelength 500 run. A thin film of thickness 2 μm and refractive index 1.5 is introduced in the path of the upper beam. The location of the central maximum will

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a

remain unshifted

b

shift downward by nearly two fringes

c

shift upward by nearly two fringes

d

shift downward by 10 fringes

answer is C.

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Detailed Solution

If shift is equal to n fringes width, thenn=(μ−1)tλ=(1.5−1) × 2 × 10−6500 × 10−9=1500 × 103 = 2Since a thin film is introduced in upper beam. So shift will be upward.
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