First slide

Diffraction

Question

In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be $0.2 °$ . What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? $(μ_{water} = 4 / 3)$

Moderate

A

$0.1 °$
B

$0.266 °$
C

$0.15 °$
D

$0.05 °$

Solution

$Angular width for first minima in Young's double slit experiment, θ = \frac{λ}{a} experiment, θ = \frac{λ}{a} For given value of a, θ \propto λ \frac{θ}{θ_{w}} = \frac{λ}{λ_{w}} = \frac{λ}{\frac{λ}{μ}} = μ \Rightarrow θ_{w} = \frac{θ}{μ} = \frac{0.2 °}{\frac{4}{3}} = 0.15 °$

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