In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? μwater =4/3

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0.1°

0.266°

0.15°

0.05°

answer is C.

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Detailed Solution

Angular width for first minima in Young's double slit experiment, θ=λa experiment, θ=λa For given value of a,θ∝λ θθw=λλw=λλμ=μ⇒θw=θμ=0.2°43=0.15°

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