First slide

Young's double slit Experiment

Question

In a double slit interference experiment the distance between the slits is 0.05 cm and screen is 2 m away from the slits. The wavelength of light is 6.0 x10^-5 cm The distance between the fringes is

Easy

A

0.24 cm
B

2.21cm
C

1.28cm
D

0.12 cm

Solution

$β = \frac{λD}{2 d} = \frac{6 \cdot 0 \times 10^{- 5} \times 200}{0 \cdot 05} = 0 \cdot 24 cm$

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