Q.

In a double slit interference experiment the distance between the slits is 0.05 cm and screen is 2 m away from the slits. The wavelength of light is 6.0 x10-5 cm The distance between the fringes is

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a

0.24 cm

b

2.21cm

c

1.28cm

d

0.12 cm

answer is A.

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Detailed Solution

β=λD2d=6⋅0×10−5×2000⋅05=0⋅24cm
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In a double slit interference experiment the distance between the slits is 0.05 cm and screen is 2 m away from the slits. The wavelength of light is 6.0 x10-5 cm The distance between the fringes is