First slide

Young's double slit Experiment

Question

In a double-slit experiment, instead of taking slits of equal width, one slit is made twice as wide as the other. Then, in the interference pattern

Moderate

A

the intensities of both the maxima and the minima increases
B

the intensity of the maximum increase and minima has zero intensity
C

the intensity of the maxima decreases and that of minima increases
D

the intensity of the maxima decreases and the minima has zero intensity

Solution

when slit are of equal width $\begin{array}{l} I_{\max} = I_{0} + I_{0} + 2 \sqrt{I_{0} I_{0}} = 4 I_{0} \\ I_{\min} = I_{0} + I_{0} - 2 \sqrt{I_{0} I_{0}} = 0 \end{array}$
When slit are of unequal width, intensity from one slit would increase to twice then
$\begin{array}{l} I_{n e w \max} = 2 I_{0} + I_{0} + 2 \sqrt{2 I_{0} I_{0}} = 5.83 I_{0} \\ I_{n e w \min} = 2 I_{0} + I_{0} - 2 \sqrt{2 I_{0} I_{0}} = 0.17 I_{0} \end{array}$
Therefore intensities for both the maxima and minima increase.

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