Q.
A doubly ionised Lithium atom is excited from its ground state (n=1) to n=3 state. The wavelengths of the spectral lines for corresponding transition are given by λ32,λ31 and λ21. The value of λ32λ31 and Λ21λ31 are respectively
see full answer
Want to Fund your own JEE / NEET / Foundation preparation ??
Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya
a
8.1, 0.67
b
8.1, 1.2
c
6.4, 1.2
d
6.4, 0.67
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
1λ=R1n12−1n22⇒1λ32=536R⇒λ32=365R Similarly λ31=98R&λ21=43R ∴ λ32λ31=6.4 and λ21λ31=1.2
Watch 3-min video & get full concept clarity