A doubly ionized Li2+ ion in the ground state absorbs 108.8 eV of energy. Find the increase in angular momentum of electron. take h=6.63×10−34J−s

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Detailed Solution

En=−13.6n2Z2Z=3, En=−122.4n2E1=−122.4 eVE2=−30.6 eVE3=−13.6 eVE3−E1=−13.6−−122.4=108.8 eVChange in angular momentum =3h2π−h2π =2h2π =2.11×10−34

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