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Q.

The driver of a car travelling at a speed of 60 km/hr applies the brake, and the car stops after covering a distance of 20 m. If the car is travelling at twice its speed, i.e., 120 km/hr, then the stopping distance will be

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a

20 m

b

40 m

c

60 m

d

80 m

answer is D.

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Detailed Solution

Let ‘a’ be the retardationν2=u2−2as∴u12−2as1=0⇒u12=2as1After the velocity is doubledu22=2as2∴u2u12=s2s1⇒120602=s220or  s2 = 80 m.
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