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The driver of a 1200 kg car notices that the car slows from 20 m/s to 15 m/s as it covers a distance of 125 m along level ground. How large a force opposes the motion?

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answer is 4.

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Detailed Solution

According to work-energy theoremW=F.S=12mv2−u2F=1200×400−2252×125=840 N

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