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Work Energy Theorem

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Question

The driver of a 1200 kg car notices that the car slows from 20 m/s to 15 m/s as it covers a distance of 125 m along level ground. How large a force opposes the motion?

Easy
Solution

According to work-energy theorem

W=F.S=12mv2u2F=1200×4002252×125=840N


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