First slide

Work Energy Theorem

Question

The driver of a 1200 kg car notices that the car slows from 20 m/s to 15 m/s as it covers a distance of 125 m along level ground. How large a force opposes the motion?

Easy

Solution

According to work-energy theorem
$\begin{array}{l} W = F . S = \frac{1}{2} m (v^{2} - u^{2}) \\ F = \frac{1200 \times (400 - 225)}{2 \times 125} = 840 N \end{array}$

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