First slide

Viscosity

Question

A drop of radius 0 .1 mm and density 10 g/cm³ falls freely under gravity through a distance ft before entering the water. After entering the water the velocity of the ball does not change. Given that g =10 m / s². What is the value of h ? The viscosity of water =10 x 10^-6 P

Moderate

A

10 m
B

20 m
C

40 m
D

80 m

Solution

Velocity acquired by the drop is equal to terminal velocity
$\sqrt{(2 gh)} = \frac{2}{9} [\frac{(ρ - σ)}{η}] r^{2} g r = 0 \cdot 1 mm = 10^{- 2} cm, ρ = 10 g / {cm}^{3}, σ = 1 g / {cm}^{3} η = 10 \times 10^{- 6} Pρ = 100 \times 10^{- 6} P = 10^{- 4} P h = 20 m$

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