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Q.

A drop of water is divided in 27 equal droplets. If ΔP1 and ΔP2 be the excess pressures in the big drop and smaller droplet respectively, then ΔP1/ΔP2 is equal to

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a

2/3

b

1

c

3

d

1/3

answer is D.

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Detailed Solution

43πr3×27=43×R3⇒r=R3Now ΔP1=2SR and ΔP2=2Sr=2SR/3=3ΔP2∴ ΔP1ΔP2=13

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